aherntech/spider-syn · Datasets at Hugging Face

What are the average score and average staff number of all shops?

SELECT avg(num_of_staff) , avg(score) FROM shop

What are the average score and average employee number of all shops?

coffee_shop

Find the id and address of the shops whose score is below the average score.

SELECT shop_id , address FROM shop WHERE score < (SELECT avg(score) FROM shop)

Find the id and location of the shops whose score is below the average score.

coffee_shop

Find the address and staff number of the shops that do not have any happy hour.

SELECT address , num_of_staff FROM shop WHERE shop_id NOT IN (SELECT shop_id FROM happy_hour)

Find the location and employee number of the shops that do not have any happy hour.

coffee_shop

What are the id and address of the shops which have a happy hour in May?

SELECT t1.address , t1.shop_id FROM shop AS t1 JOIN happy_hour AS t2 ON t1.shop_id = t2.shop_id WHERE MONTH = 'May'

What are the id and location of the shops which have a happy hour in May?

coffee_shop

which shop has happy hour most frequently? List its id and number of happy hours.

SELECT shop_id , count(*) FROM happy_hour GROUP BY shop_id ORDER BY count(*) DESC LIMIT 1

which store has happy hour most frequently? List its id and number of happy hours.

coffee_shop

Which month has the most happy hours?

SELECT MONTH FROM happy_hour GROUP BY MONTH ORDER BY count(*) DESC LIMIT 1

Which month has the most happy hours?

coffee_shop

Which months have more than 2 happy hours?

SELECT MONTH FROM happy_hour GROUP BY MONTH HAVING count(*) > 2

Which months have more than 2 happy hours?

coffee_shop

How many albums are there?

SELECT count(*) FROM ALBUM

How many albums are there?

chinook_1

Find the number of albums.

SELECT count(*) FROM ALBUM

Find the number of albums.

chinook_1

List the names of all music genres.

SELECT Name FROM GENRE

List the names of all music types.

chinook_1

What are the names of different music genres?

SELECT Name FROM GENRE

What are the names of different music genres?

chinook_1

Find all the customer information in state NY.

SELECT * FROM CUSTOMER WHERE State = "NY"

Find all the client information in state NY.

chinook_1

What is all the customer information for customers in NY state?

SELECT * FROM CUSTOMER WHERE State = "NY"

What is all the client information for customers in NY state?

chinook_1

What are the first names and last names of the employees who live in Calgary city.

SELECT FirstName , LastName FROM EMPLOYEE WHERE City = "Calgary"

What are the full names of the employees who live in Calgary city.

chinook_1

Find the full names of employees living in the city of Calgary.

SELECT FirstName , LastName FROM EMPLOYEE WHERE City = "Calgary"

Find the full names of employees living in the city of Calgary.

chinook_1

What are the distinct billing countries of the invoices?

SELECT distinct BillingCountry FROM INVOICE

What are the different billing countries of the invoices?

chinook_1

Find the different billing countries for all invoices.

SELECT distinct BillingCountry FROM INVOICE

Find the different billing countries for all invoices.

chinook_1

Find the names of all artists that have "a" in their names.

SELECT Name FROM ARTIST WHERE Name LIKE "%a%"

Find the names of all artists that have "a" in their names.

chinook_1

What are the names of artist who have the letter 'a' in their names?

SELECT Name FROM ARTIST WHERE Name LIKE "%a%"

What are the names of artist who have the letter 'a' in their names?

chinook_1

Find the title of all the albums of the artist "AC/DC".

SELECT Title FROM ALBUM AS T1 JOIN ARTIST AS T2 ON T1.ArtistId = T2.ArtistId WHERE T2.Name = "AC/DC"

Find the name of all the albums of the artist "AC/DC".

chinook_1

What are the titles of albums by the artist "AC/DC"?

SELECT Title FROM ALBUM AS T1 JOIN ARTIST AS T2 ON T1.ArtistId = T2.ArtistId WHERE T2.Name = "AC/DC"

What are the names of albums by the artist "AC/DC"?

chinook_1

Hom many albums does the artist "Metallica" have?

SELECT COUNT(*) FROM ALBUM AS T1 JOIN ARTIST AS T2 ON T1.ArtistId = T2.ArtistId WHERE T2.Name = "Metallica"

Hom many albums does the artist "Metallica" have?

chinook_1

Find the number of albums by the artist "Metallica".

SELECT COUNT(*) FROM ALBUM AS T1 JOIN ARTIST AS T2 ON T1.ArtistId = T2.ArtistId WHERE T2.Name = "Metallica"

Find the number of albums by the artist "Metallica".

chinook_1

Which artist does the album "Balls to the Wall" belong to?

SELECT T2.Name FROM ALBUM AS T1 JOIN ARTIST AS T2 ON T1.ArtistId = T2.ArtistId WHERE T1.Title = "Balls to the Wall"

Which artist does the album "Balls to the Wall" belong to?

chinook_1

Find the name of the artist who made the album "Balls to the Wall".

SELECT T2.Name FROM ALBUM AS T1 JOIN ARTIST AS T2 ON T1.ArtistId = T2.ArtistId WHERE T1.Title = "Balls to the Wall"

Find the name of the artist who made the album "Balls to the Wall".

chinook_1

Which artist has the most albums?

SELECT T2.Name FROM ALBUM AS T1 JOIN ARTIST AS T2 ON T1.ArtistId = T2.ArtistId GROUP BY T2.Name ORDER BY COUNT(*) DESC LIMIT 1

Which artist has the most albums?

chinook_1

What is the name of the artist with the greatest number of albums?

SELECT T2.Name FROM ALBUM AS T1 JOIN ARTIST AS T2 ON T1.ArtistId = T2.ArtistId GROUP BY T2.Name ORDER BY COUNT(*) DESC LIMIT 1

What is the name of the artist with the greatest number of albums?

chinook_1

Find the names of all the tracks that contain the word "you".

SELECT Name FROM TRACK WHERE Name LIKE '%you%'

Find the names of all the tracks that contain the word "you".

chinook_1

What are the names of tracks that contain the the word you in them?

SELECT Name FROM TRACK WHERE Name LIKE '%you%'

What are the names of tracks that contain the the word you in them?

chinook_1

What is the average unit price of all the tracks?

SELECT AVG(UnitPrice) FROM TRACK

What is the average unit price of all the tracks?

chinook_1

Find the average unit price for a track.

SELECT AVG(UnitPrice) FROM TRACK

Find the average unit price for a track.

chinook_1

What are the durations of the longest and the shortest tracks in milliseconds?

SELECT max(Milliseconds) , min(Milliseconds) FROM TRACK

What are the durations of the longest and the shortest tracks in milliseconds?

chinook_1

Find the maximum and minimum durations of tracks in milliseconds.

SELECT max(Milliseconds) , min(Milliseconds) FROM TRACK

Find the maximum and minimum durations of tracks in milliseconds.

chinook_1

Show the album names, ids and the number of tracks for each album.

SELECT T1.Title , T2.AlbumID , COUNT(*) FROM ALBUM AS T1 JOIN TRACK AS T2 ON T1.AlbumId = T2.AlbumId GROUP BY T2.AlbumID

Show the album names, ids and the number of tracks for each album.

chinook_1

What are the names and ids of the different albums, and how many tracks are on each?

SELECT T1.Title , T2.AlbumID , COUNT(*) FROM ALBUM AS T1 JOIN TRACK AS T2 ON T1.AlbumId = T2.AlbumId GROUP BY T2.AlbumID

What are the names and ids of the different albums, and how many tracks are on each?

chinook_1

What is the name of the most common genre in all tracks?

SELECT T1.Name FROM GENRE AS T1 JOIN TRACK AS T2 ON T1.GenreId = T2.GenreId GROUP BY T2.GenreId ORDER BY COUNT(*) DESC LIMIT 1

What is the name of the most common genre in all tracks?

chinook_1

Find the name of the genre that is most frequent across all tracks.

SELECT T1.Name FROM GENRE AS T1 JOIN TRACK AS T2 ON T1.GenreId = T2.GenreId GROUP BY T2.GenreId ORDER BY COUNT(*) DESC LIMIT 1

Find the name of the genre that is most frequent across all tracks.

chinook_1

What is the least common media type in all tracks?

SELECT T1.Name FROM MEDIATYPE AS T1 JOIN TRACK AS T2 ON T1.MediaTypeId = T2.MediaTypeId GROUP BY T2.MediaTypeId ORDER BY COUNT(*) ASC LIMIT 1

What is the least common media type in all tracks?

chinook_1

What is the name of the media type that is least common across all tracks?

SELECT T1.Name FROM MEDIATYPE AS T1 JOIN TRACK AS T2 ON T1.MediaTypeId = T2.MediaTypeId GROUP BY T2.MediaTypeId ORDER BY COUNT(*) ASC LIMIT 1

What is the name of the media type that is least common across all tracks?

chinook_1

Show the album names and ids for albums that contain tracks with unit price bigger than 1.

SELECT T1.Title , T2.AlbumID FROM ALBUM AS T1 JOIN TRACK AS T2 ON T1.AlbumId = T2.AlbumId WHERE T2.UnitPrice > 1 GROUP BY T2.AlbumID

Show the album names and ids for albums that contain tracks with unit price bigger than 1.

chinook_1

What are the titles and ids for albums containing tracks with unit price greater than 1?

SELECT T1.Title , T2.AlbumID FROM ALBUM AS T1 JOIN TRACK AS T2 ON T1.AlbumId = T2.AlbumId WHERE T2.UnitPrice > 1 GROUP BY T2.AlbumID

What are the names and ids for albums containing tracks with unit price greater than 1?

chinook_1

How many tracks belong to rock genre?

SELECT COUNT(*) FROM GENRE AS T1 JOIN TRACK AS T2 ON T1.GenreId = T2.GenreId WHERE T1.Name = "Rock"

How many tracks belong to rock genre?

chinook_1

Count the number of tracks that are part of the rock genre.

SELECT COUNT(*) FROM GENRE AS T1 JOIN TRACK AS T2 ON T1.GenreId = T2.GenreId WHERE T1.Name = "Rock"

Count the number of tracks that are part of the rock genre.

chinook_1

What is the average unit price of tracks that belong to Jazz genre?

SELECT AVG(UnitPrice) FROM GENRE AS T1 JOIN TRACK AS T2 ON T1.GenreId = T2.GenreId WHERE T1.Name = "Jazz"

What is the average unit price of tracks that belong to Jazz genre?

chinook_1

Find the average unit price of jazz tracks.

SELECT AVG(UnitPrice) FROM GENRE AS T1 JOIN TRACK AS T2 ON T1.GenreId = T2.GenreId WHERE T1.Name = "Jazz"

Find the average unit price of jazz tracks.

chinook_1

What is the first name and last name of the customer that has email "luisg@embraer.com.br"?

SELECT FirstName , LastName FROM CUSTOMER WHERE Email = "luisg@embraer.com.br"

What is the full name of the customer that has email "luisg@embraer.com.br"?

chinook_1

Find the full name of the customer with the email "luisg@embraer.com.br".

SELECT FirstName , LastName FROM CUSTOMER WHERE Email = "luisg@embraer.com.br"

Find the full name of the customer with the email "luisg@embraer.com.br".

chinook_1

How many customers have email that contains "gmail.com"?

SELECT COUNT(*) FROM CUSTOMER WHERE Email LIKE "%gmail.com%"

How many clients have email that contains "gmail.com"?

chinook_1

Count the number of customers that have an email containing "gmail.com".

SELECT COUNT(*) FROM CUSTOMER WHERE Email LIKE "%gmail.com%"

Count the number of customers that have an email containing "gmail.com".

chinook_1

What is the first name and last name employee helps the customer with first name Leonie?

SELECT T2.FirstName , T2.LastName FROM CUSTOMER AS T1 JOIN EMPLOYEE AS T2 ON T1.SupportRepId = T2.EmployeeId WHERE T1.FirstName = "Leonie"

What is the full name employee helps the customer with first name Leonie?

chinook_1

Find the full names of employees who help customers with the first name Leonie.

SELECT T2.FirstName , T2.LastName FROM CUSTOMER AS T1 JOIN EMPLOYEE AS T2 ON T1.SupportRepId = T2.EmployeeId WHERE T1.FirstName = "Leonie"

Find the full names of employees who help customers with the first name Leonie.

chinook_1

What city does the employee who helps the customer with postal code 70174 live in?

SELECT T2.City FROM CUSTOMER AS T1 JOIN EMPLOYEE AS T2 ON T1.SupportRepId = T2.EmployeeId WHERE T1.PostalCode = "70174"

What city does the employee who helps the customer with postal code 70174 live in?

chinook_1

Find the cities corresponding to employees who help customers with the postal code 70174.

SELECT T2.City FROM CUSTOMER AS T1 JOIN EMPLOYEE AS T2 ON T1.SupportRepId = T2.EmployeeId WHERE T1.PostalCode = "70174"

Find the cities corresponding to employees who help customers with the postal code 70174.

chinook_1

How many distinct cities does the employees live in?

SELECT COUNT(DISTINCT city) FROM EMPLOYEE

How many different cities does the employees live in?

chinook_1

Find the number of different cities that employees live in.

SELECT COUNT(DISTINCT city) FROM EMPLOYEE

Find the number of different cities that employees live in.

chinook_1

Find all invoice dates corresponding to customers with first name Astrid and last name Gruber.

SELECT T2.InvoiceDate FROM CUSTOMER AS T1 JOIN INVOICE AS T2 ON T1.CustomerId = T2.CustomerId WHERE T1.FirstName = "Astrid" AND LastName = "Gruber"

Find all invoice dates corresponding to customers with first name Astrid and last name Gruber.

chinook_1

What are the invoice dates for customers with the first name Astrid and the last name Gruber?

SELECT T2.InvoiceDate FROM CUSTOMER AS T1 JOIN INVOICE AS T2 ON T1.CustomerId = T2.CustomerId WHERE T1.FirstName = "Astrid" AND LastName = "Gruber"

What are the invoice dates for customers with the first name Astrid and the last name Gruber?

chinook_1

Find all the customer last names that do not have invoice totals larger than 20.

SELECT LastName FROM CUSTOMER EXCEPT SELECT T1.LastName FROM CUSTOMER AS T1 JOIN Invoice AS T2 ON T1.CustomerId = T2.CustomerId WHERE T2.total > 20

Find all the customer family names that do not have invoice totals larger than 20.

chinook_1

What are the last names of customers without invoice totals exceeding 20?

SELECT LastName FROM CUSTOMER EXCEPT SELECT T1.LastName FROM CUSTOMER AS T1 JOIN Invoice AS T2 ON T1.CustomerId = T2.CustomerId WHERE T2.total > 20

What are the family names of customers without invoice totals exceeding 20?

chinook_1

Find the first names of all customers that live in Brazil and have an invoice.

SELECT DISTINCT T1.FirstName FROM CUSTOMER AS T1 JOIN INVOICE AS T2 ON T1.CustomerId = T2.CustomerId WHERE T1.country = "Brazil"

Find the forename of all customers that live in Brazil and have an invoice.

chinook_1

What are the different first names for customers from Brazil who have also had an invoice?

SELECT DISTINCT T1.FirstName FROM CUSTOMER AS T1 JOIN INVOICE AS T2 ON T1.CustomerId = T2.CustomerId WHERE T1.country = "Brazil"

What are the different forename for customers from Brazil who have also had an invoice?

chinook_1

Find the address of all customers that live in Germany and have invoice.

SELECT DISTINCT T1.Address FROM CUSTOMER AS T1 JOIN INVOICE AS T2 ON T1.CustomerId = T2.CustomerId WHERE T1.country = "Germany"

Find the location of all customers that live in Germany and have invoice.

chinook_1

What are the addresses of customers living in Germany who have had an invoice?

SELECT DISTINCT T1.Address FROM CUSTOMER AS T1 JOIN INVOICE AS T2 ON T1.CustomerId = T2.CustomerId WHERE T1.country = "Germany"

What are the location of customers living in Germany who have had an invoice?

chinook_1

List the phone numbers of all employees.

SELECT Phone FROM EMPLOYEE

List the telephone numbers of all employees.

chinook_1

What are the phone numbers for each employee?

SELECT Phone FROM EMPLOYEE

What are the mobile numbers for each employee?

chinook_1

How many tracks are in the AAC audio file media type?

SELECT COUNT(*) FROM MEDIATYPE AS T1 JOIN TRACK AS T2 ON T1.MediaTypeId = T2.MediaTypeId WHERE T1.Name = "AAC audio file"

How many tracks are in the AAC audio file media type?

chinook_1

Count the number of tracks that are of the media type "AAC audio file".

SELECT COUNT(*) FROM MEDIATYPE AS T1 JOIN TRACK AS T2 ON T1.MediaTypeId = T2.MediaTypeId WHERE T1.Name = "AAC audio file"

Count the number of tracks that are of the media type "AAC audio file".

chinook_1

What is the average duration in milliseconds of tracks that belong to Latin or Pop genre?

SELECT AVG(Milliseconds) FROM GENRE AS T1 JOIN TRACK AS T2 ON T1.GenreId = T2.GenreId WHERE T1.Name = "Latin" OR T1.Name = "Pop"

What is the average duration in milliseconds of tracks that belong to Latin or Pop genre?

chinook_1

Find the average millisecond length of Latin and Pop tracks.

SELECT AVG(Milliseconds) FROM GENRE AS T1 JOIN TRACK AS T2 ON T1.GenreId = T2.GenreId WHERE T1.Name = "Latin" OR T1.Name = "Pop"

Find the average millisecond length of Latin and Pop tracks.

chinook_1

Please show the employee first names and ids of employees who serve at least 10 customers.

SELECT T1.FirstName , T1.SupportRepId FROM CUSTOMER AS T1 JOIN EMPLOYEE AS T2 ON T1.SupportRepId = T2.EmployeeId GROUP BY T1.SupportRepId HAVING COUNT(*) >= 10

Please show the employee forename and ids of employees who serve at least 10 customers.

chinook_1

What are the first names and support rep ids for employees serving 10 or more customers?

SELECT T1.FirstName , T1.SupportRepId FROM CUSTOMER AS T1 JOIN EMPLOYEE AS T2 ON T1.SupportRepId = T2.EmployeeId GROUP BY T1.SupportRepId HAVING COUNT(*) >= 10

What are the forename and support rep ids for employees serving 10 or more customers?

chinook_1

Please show the employee last names that serves no more than 20 customers.

SELECT T1.LastName FROM CUSTOMER AS T1 JOIN EMPLOYEE AS T2 ON T1.SupportRepId = T2.EmployeeId GROUP BY T1.SupportRepId HAVING COUNT(*) <= 20

Please show the employee family name that serves no more than 20 customers.

chinook_1

What are the last names of employees who serve at most 20 customers?

SELECT T1.LastName FROM CUSTOMER AS T1 JOIN EMPLOYEE AS T2 ON T1.SupportRepId = T2.EmployeeId GROUP BY T1.SupportRepId HAVING COUNT(*) <= 20

What are the family name of employees who serve at most 20 customers?

chinook_1

Please list all album titles in alphabetical order.

SELECT Title FROM ALBUM ORDER BY Title

Please list all album names in alphabetical order.

chinook_1

What are all the album titles, in alphabetical order?

SELECT Title FROM ALBUM ORDER BY Title

What are all the album names, in alphabetical order?

chinook_1

Please list the name and id of all artists that have at least 3 albums in alphabetical order.

SELECT T2.Name , T1.ArtistId FROM ALBUM AS T1 JOIN ARTIST AS T2 ON T1.ArtistId = T2.ArtistID GROUP BY T1.ArtistId HAVING COUNT(*) >= 3 ORDER BY T2.Name

Please list the name and id of all artists that have at least 3 albums in alphabetical order.

chinook_1

What are the names and ids of artists with 3 or more albums, listed in alphabetical order?

SELECT T2.Name , T1.ArtistId FROM ALBUM AS T1 JOIN ARTIST AS T2 ON T1.ArtistId = T2.ArtistID GROUP BY T1.ArtistId HAVING COUNT(*) >= 3 ORDER BY T2.Name

What are the names and ids of artists with 3 or more albums, listed in alphabetical order?

chinook_1

Find the names of artists that do not have any albums.

SELECT Name FROM ARTIST EXCEPT SELECT T2.Name FROM ALBUM AS T1 JOIN ARTIST AS T2 ON T1.ArtistId = T2.ArtistId

Find the names of artists that do not have any albums.

chinook_1

What are the names of artists who have not released any albums?

SELECT Name FROM ARTIST EXCEPT SELECT T2.Name FROM ALBUM AS T1 JOIN ARTIST AS T2 ON T1.ArtistId = T2.ArtistId

What are the names of artists who have not released any albums?

chinook_1

What is the average unit price of rock tracks?

SELECT AVG(T2.UnitPrice) FROM GENRE AS T1 JOIN TRACK AS T2 ON T1.GenreId = T2.GenreId WHERE T1.Name = "Rock"

What is the average unit price of rock tracks?

chinook_1

Find the average unit price of tracks from the Rock genre.

SELECT AVG(T2.UnitPrice) FROM GENRE AS T1 JOIN TRACK AS T2 ON T1.GenreId = T2.GenreId WHERE T1.Name = "Rock"

Find the average unit price of tracks from the Rock genre.

chinook_1

What are the duration of the longest and shortest pop tracks in milliseconds?

SELECT max(Milliseconds) , min(Milliseconds) FROM GENRE AS T1 JOIN TRACK AS T2 ON T1.GenreId = T2.GenreId WHERE T1.Name = "Pop"

What are the duration of the longest and shortest pop tracks in milliseconds?

chinook_1

Find the maximum and minimum millisecond lengths of pop tracks.

SELECT max(Milliseconds) , min(Milliseconds) FROM GENRE AS T1 JOIN TRACK AS T2 ON T1.GenreId = T2.GenreId WHERE T1.Name = "Pop"

Find the maximum and minimum millisecond lengths of pop tracks.

chinook_1

What are the birth dates of employees living in Edmonton?

SELECT BirthDate FROM EMPLOYEE WHERE City = "Edmonton"

What are the birthdays of employees living in Edmonton?

chinook_1

Find the birth dates corresponding to employees who live in the city of Edmonton.

SELECT BirthDate FROM EMPLOYEE WHERE City = "Edmonton"

Find the birthdays corresponding to employees who live in the city of Edmonton.

chinook_1

What are the distinct unit prices of all tracks?

SELECT distinct UnitPrice FROM TRACK

What are the different unit prices of all tracks?

chinook_1

Find the distinct unit prices for tracks.

SELECT distinct UnitPrice FROM TRACK

Find the different unit prices for tracks.

chinook_1

How many artists do not have any album?

SELECT count(*) FROM ARTIST WHERE artistid NOT IN(SELECT artistid FROM ALBUM)

How many artists do not have any album?

chinook_1

Cound the number of artists who have not released an album.

SELECT count(*) FROM ARTIST WHERE artistid NOT IN(SELECT artistid FROM ALBUM)

Cound the number of artists who have not released an album.

chinook_1

What are the album titles for albums containing both 'Reggae' and 'Rock' genre tracks?

SELECT T1.Title FROM Album AS T1 JOIN Track AS T2 ON T1.AlbumId = T2.AlbumId JOIN Genre AS T3 ON T2.GenreID = T3.GenreID WHERE T3.Name = 'Reggae' INTERSECT SELECT T1.Title FROM Album AS T1 JOIN Track AS T2 ON T1.AlbumId = T2.AlbumId JOIN Genre AS T3 ON T2.GenreID = T3.GenreID WHERE T3.Name = 'Rock'

What are the album names for albums containing both 'Reggae' and 'Rock' genre tracks?

chinook_1

Find the titles of albums that contain tracks of both the Reggae and Rock genres.

SELECT T1.Title FROM Album AS T1 JOIN Track AS T2 ON T1.AlbumId = T2.AlbumId JOIN Genre AS T3 ON T2.GenreID = T3.GenreID WHERE T3.Name = 'Reggae' INTERSECT SELECT T1.Title FROM Album AS T1 JOIN Track AS T2 ON T1.AlbumId = T2.AlbumId JOIN Genre AS T3 ON T2.GenreID = T3.GenreID WHERE T3.Name = 'Rock'

Find the names of albums that contain tracks of both the Reggae and Rock genres.

chinook_1

Find all the phone numbers.

SELECT customer_phone FROM available_policies

Find all the telephone numbers.

insurance_fnol

What are all the phone numbers?

SELECT customer_phone FROM available_policies

What are all the telephone numbers?

insurance_fnol

What are the customer phone numbers under the policy "Life Insurance"?

SELECT customer_phone FROM available_policies WHERE policy_type_code = "Life Insurance"

What are the client mobile numbers under the policy "Life Insurance"?

insurance_fnol

What are the phone numbers of customers using the policy with the code "Life Insurance"?

SELECT customer_phone FROM available_policies WHERE policy_type_code = "Life Insurance"

What are the mobile numbers of clients using the policy with the code "Life Insurance"?

insurance_fnol

Which policy type has the most records in the database?

SELECT policy_type_code FROM available_policies GROUP BY policy_type_code ORDER BY count(*) DESC LIMIT 1

Which insurance type has the most records in the database?

insurance_fnol

Which policy type appears most frequently in the available policies?

SELECT policy_type_code FROM available_policies GROUP BY policy_type_code ORDER BY count(*) DESC LIMIT 1

Which insurance type appears most frequently in the available policies?

insurance_fnol

What are all the customer phone numbers under the most popular policy type?

SELECT customer_phone FROM available_policies WHERE policy_type_code = (SELECT policy_type_code FROM available_policies GROUP BY policy_type_code ORDER BY count(*) DESC LIMIT 1)

What are all the client telephone numbers under the most popular policy type?

insurance_fnol

Find the phone numbers of customers using the most common policy type among the available policies.

SELECT customer_phone FROM available_policies WHERE policy_type_code = (SELECT policy_type_code FROM available_policies GROUP BY policy_type_code ORDER BY count(*) DESC LIMIT 1)

Find the telephone numbers of clients using the most common policy type among the available policies.

insurance_fnol

Find the policy type used by more than 4 customers.

SELECT policy_type_code FROM available_policies GROUP BY policy_type_code HAVING count(*) > 4

Find the insurance category used by more than 4 customers.

insurance_fnol